关于php继承的疑惑
- PHP code
<?php class A {
[color=#FF0000]private[/color] $name = "Nciaer";
public function say() {
echo $this -> name . "
";
}
}
class B extends A {
public $name = "Fansa";
}
$b = new B();
$b -> say();
?>
输出结果：
Nciaer
----------------------------
- PHP code
<?php class A {
[color=#FF0000]public[/color] $name = "Nciaer";
public function say() {
echo $this -> name . "
";
}
}
class B extends A {
public $name = "Fansa";
}
$b = new B();
$b -> say();
?>
输出结果：
Fansa
为什么父类变量$name为public的时候，$b调用成员方法say()输出子类的$name;
当父类变量$name为private时，$b调用成员方法say()输出父类的$name;
------解决方案--------------------
private 私有的
怎么能被继承呢？