关于initialize如何实现

假设有class a、b、base，a、b都继承base，
a、b允许有一个方法initialize();

如果new N次：
$obj = new a();
$obj = new a();
$obj = new a();
$obj = new b();
$obj = new b();
$obj = new b();

只执行一次 a->initialize(); 和一次 b->initialize(); 

initialize在框架中主要是替代__construct方法。
phalcon实现了这个功能，但是phalcon是C编写的框架，纯PHP能实现这个效果么？

回复讨论(解决方案)

class bass {  function __construct() {    $this->_initialize();  }  function _initialize() {    static $v;    @$v++;    if($v == 1 && method_exists($this, 'initialize')) $this->initialize();  }}class a extends bass {  function initialize() {    echo __CLASS__;  }}class b extends bass {  function initialize() {    echo __CLASS__;  }}$obj = new a();$obj = new a();$obj = new a();$obj = new b();$obj = new b();$obj = new b();

class bass {  function __construct() {    $this->_initialize();  }  function _initialize() {    static $v;    @$v++;    if($v == 1 && method_exists($this, 'initialize')) $this->initialize();  }}class a extends bass {  function initialize() {    echo __CLASS__;  }}class b extends bass {  function initialize() {    echo __CLASS__;  }}$obj = new a();$obj = new a();$obj = new a();$obj = new b();$obj = new b();$obj = new b();

@$v++;
问一下这句为什么要加“@”符合？