菜鸟初次接触php与mysql数据库的连接操作,模仿书上写了以下代码,发现可以连接上数据库,但是sql语句却总是没有被执行,sql语句是没问题的,在phpMyAdmin中是可以成功执行的,可是到了这里就不行,求大神搭救看看问题出在哪
<?php $host="localhost"; $userName="cheng"; $password="11111111"; $dbName="db_student"; $connID=mysqli_connect($host,$userName,$password); /*if ($connID){echo "ok";} else {echo "error";} */ mysqli_select_db($connID,$dbName); mysqli_query($connID,"set names gbk"); //$query=mysqli_query($connID,"SELECT sno,sname,class,chinese,math,english FROM tb_student"); $result=mysqli_query($connID,"INSERT INTO tb_student(sno, sname, class, chinese, math, english) VALUES ('012531','sbsb','12ji','70','70','70')"); if ($result){echo "ok";} else die('Error: ' . mysql_error()); mysqli_close($connID);
回复讨论(解决方案)
是报什么错?
程序输出了什么?
程序没有报错,但是数据库中没有成功插入
是报什么错?
输出error加空字符串
程序输出了什么?
哈哈大神不好意思,是我自己搞了个乌龙,我的mysql数据库中没有给这个用户权限,所以修改不了数据库,给完权限之后就好了,谢谢大神
程序输出了什么?
<?php $host="localhost"; $userName="cheng"; $password="11111111"; $dbName="db_student"; $connID=mysqli_connect($host,$userName,$password,$dbName); mysqli_query($connID,"set names gbk"); //$query=mysqli_query($connID,"SELECT sno,sname,class,chinese,math,english FROM tb_student"); $result=mysqli_query($connID,"INSERT INTO tb_student(sno, sname, class, chinese, math, english) VALUES ('012531','sbsb','12ji','70','70','70')"); if ($result){echo "ok";} else die('Error: ' . mysql_error()); mysqli_close($connID);
你这样试一下
if ($result){echo "ok";}
else die('Error: ' . mysqli_error());
mysqli_close($connID);