多维数组判断

city[x] [y] 
x储存省的id
y储存x省的城市的id
如果city[x]下没有数据  
说明省是空的 可以删除
反之不能           怎么解？

回复讨论(解决方案)

count(city[x]) == 0

count(city[x]) == 0

foreach($city as $key->$item) {  if(count($itrm) <== 0) unset($city[$key]);}

foreach($city as $key->$item) {  if(count($itrm) <== 0) unset($city[$key]);}