在网上找了一个随机取数语句，结合了自己的需求，运行出错，
看了半天没发现出错的地方，求指点
$str="select * from dizhi where shijiancuo>'$times' GROUP BY user HAVING COUNT(user) > 4 AS t1 JOIN (SELECT ROUND(RAND() * (SELECT MAX(id) FROM dizhi)) AS id) AS t2 WHERE t1.id >= t2.id ORDER BY t1.id ASC LIMIT 1" ;
回复讨论(解决方案)
错误信息是什么？
Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in D:\www\AppServ\www\tuijianshuchu.php on line 23
23代码如下
$result=mysql_query($str, $con); //送出查? $rows=mysql_num_rows($result); //23行
因为是你的sql语句出错了 你把$str语句打印下看是什么东东
$str在1楼贴了
$result=mysql_query($str, $con) or die(mysql_error());
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'AS t1 JOIN (SELECT ROUND(RAND() * (SELECT MAX(id) FROM dizhi)) AS id) AS t2 ' at line 1
select * from
(select * from dizhi where shijiancuo>'$times' GROUP BY user HAVING COUNT(user) > 4) AS t1
JOIN
(SELECT ROUND(RAND() * (SELECT MAX(id) FROM dizhi)) AS id) AS t2
WHERE t1.id >= t2.id
ORDER BY t1.id ASC LIMIT 1
JOIN (SELECT ROUND(RAND() * (SELECT MAX(id) FROM dizhi)) AS id from dizhi) AS t2
8楼的不行，7楼的OK，多谢了
一直没搞明白这句的意思
(SELECT ROUND(RAND() * (SELECT MAX(id) FROM dizhi)) AS id) AS t2
网上说ROUND 函数用于把数值字段舍入为指定的小数位数，所以不太理解这语句的结果是什么
RAND 产生一个小于 1 的随机数
SELECT MAX(id) FROM dizhi 取得表 dizhi 中最大的 id 值
ROUND 四舍五入化为整数
这个查询指令的意思是：
任取表中的一个 id 值
理解了，3Q。