mysql_connect("localhost", "root", "123") or die("Could not connect: " . mysql_error()); mysql_select_db("iweibo"); $result = mysql_query("SELECT * FROM user where username like %admin%"); while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) { var_dump($row); } 报错信息：
Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\34\test.php on line 19
回复讨论(解决方案)
$result = mysql_query("SELECT * FROM user where username like '%admin%'");
肯定是SQL语句的问题，echo 你的sql语句，拿到数据库去运行就知道什么原因了。
$result = mysql_query("SELECT * FROM user where username like '%admin%'");
试一试。