无语的出错,mysql_fetch_array()

MySQL PHP 数据库连接 查询

<?phpclass Conn{	private $dbhost = "";			//服务器	private $dbuser = "";			//mysql帐号	private $dbpsw = "";			//mysql密码	private $dbchar = "";			//数据库编码类型	private $dbname = "";			//数据库名称	private $tablepre = "";			//表前缀	private $conn = NULL;			//连接对象 		/**	 * 数据库链接初始化	 */	public function __construct(){		$this->getConn();	}		public function getConn(){		$db = require_once 'config/config.php';		$this->dbhost = $db['dbhost'];		$this->dbuser = $db['dbuser'];		$this->dbpsw = $db['dbpsw'];		$this->dbchar = $db['dbchar'];		$this->dbname = $db['dbname'];		$this->tablepre = $db['tablepre'];		$this->conn = mysql_connect($this->dbhost,$this->dbuser,$this->dbpsw) or die(mysql_error()."
Mysql连接失败!");		mysql_select_db($this->dbname,$this->conn) or die(mysql_error()."
数据库访问出错");		mysql_query("set names ".$this->dbchar,$this->conn);	}		/**	 * 执行sql	 */	public function query($sql){		return mysql_query($sql,$this->conn) or die(mysql_error()."
SQL执行出错：$sql");	}		/**	 * 返回多条记录	 */	public function getDataArrays($sql,$type = MYSQL_BOTH){		$result = $this->query($sql);		$refArr = array();		while ($row = mysql_fetch_array($result,$type)){			$refArr[] = $row;		}		return $refArr;	}		/**	 * 关闭数据库链接	 */	public function closeConn(){		mysql_close($this->conn);	}}

$conn = new Conn();$sql = "select * from qj_content";$contentList = $conn->getDataArrays($sql,MYSQL_ASSOC);$conn->closeConn();

回复讨论(解决方案)

那块用红色标注的被弄成php代码了，我晕
是/**
* 返回多条记录
*/
public function getDataArrays($sql,$type = MYSQL_BOTH){
$result = $this->query($sql);
$refArr = array();
while ($row = mysql_fetch_array($result,$type)){
$refArr[] = $row;
}
return $refArr;
}

怎么都没有人来？
几次提问 不论简单还是困难都没有人来帮帮解答一下，
CSDN什么时候变得这么冷清了？

估计sql 出问题了
在while 上 echo mysql_error(); 看看

LZ看看W3C上面的例子吧



语法

mysql_fetch_array(data,array_type)

参数 描述
data 可选。规定要使用的数据指针。该数据指针是 mysql_query() 函数产生的结果。
array_type

可选。规定返回哪种结果。可能的值：

MYSQL_ASSOC - 关联数组
MYSQL_NUM - 数字数组
MYSQL_BOTH - 默认。同时产生关联和数字数组

<?php$con = mysql_connect("localhost", "hello", "321");if (!$con)  {  die('Could not connect: ' . mysql_error());  }$db_selected = mysql_select_db("test_db",$con);$sql = "SELECT * from Person WHERE Lastname='Adams'";$result = mysql_query($sql,$con);print_r(mysql_fetch_array($result));mysql_close($con);?>

query 方法改成这样

    public function query($sql){        $rs = mysql_query($sql,$this->conn) or die(mysql_error()."
SQL执行出错：$sql");        return $rs;    }